Election in Delaware
1880 United States presidential election in Delaware
|
|
| | | Nominee | Winfield S. Hancock | James A. Garfield | | Party | Democratic | Republican | Home state | Pennsylvania | Ohio | Running mate | William H. English | Chester A. Arthur | Electoral vote | 3 | 0 | Popular vote | 15,181 | 14,148 | Percentage | 51.53% | 48.03% | |
County Results Hancock 50-60% | Garfield 50-60% | |
President before election Rutherford B. Hayes Republican | Elected President James Garfield Republican | |
Elections in Delaware |
---|
|
|
|
|
|
The 1880 United States presidential election in Delaware took place on November 2, 1880, as part of the 1880 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]
Delaware was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 51.53% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 48.03% of the vote.[1]
As of 2023, this is the most recent time that a Republican won the presidency without carrying Sussex County.
Results
See also
References
- ^ a b c "1880 Presidential Election Results Delaware".