Election in Connecticut
1884 United States presidential election in Connecticut
|
|
| |  |  | | Nominee | Grover Cleveland | James G. Blaine | | | Party | Democratic | Republican | | Home state | New York | Maine | | Running mate | Thomas A. Hendricks | John A. Logan | | Electoral vote | 6 | 0 | | Popular vote | 67,182 | 65,898 | | Percentage | 48.95% | 48.01% | |
 County Results | Cleveland 40-50% 50-60% | Blaine 50-60% | |
President before election
Chester A. Arthur
Republican | Elected President
Grover Cleveland
Democratic | |
| Elections in Connecticut |
|---|
 |
| |
| State elections |
|---|
| | | Governor |
|---|
| | | Attorney General |
|---|
| | | Secretary of the State |
|---|
| | | State Treasurer |
|---|
| | | State Comptroller |
|---|
| | | State Senate |
|---|
| | | State House |
|---|
| |
|
| |
| |
| |
| |
| |
|
The 1884 United States presidential election in Connecticut took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.
Connecticut voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. Cleveland won the state by a very narrow margin of 0.94%. Cleveland was the first Democrat to win without New London County since 1844 and Middlesex County since 1832.
Results
See also
References
- ^ "1884 Presidential General Election Results - Connecticut".
