1997 Romanian Open – Doubles

Doubles
1997 Romanian Open
Final
Champions	Luis Lobo Javier Sánchez
Runners-up	Hendrik Jan Davids Daniel Orsanic
Score	7–5, 7–5
Details
Draw	16 (3WC/1Q)
Seeds	4
Events
Singles Doubles
← 1996 · Romanian Open · 1998 →

David Ekerot and Jeff Tarango were the defending champions, but Ekerot did not compete this year. Tarango teamed up with Roger Smith and lost in the first round to Luis Lobo and Javier Sánchez.

Lobo and Sánchez won the title by defeating Hendrik Jan Davids and Daniel Orsanic 7–5, 7–5 in the final.^[1]

Seeds

Draw

Key

Draw

	First round							Quarterfinals							Semifinals							Final
	1	L Lobo J Sánchez	6	6
		R Smith J Tarango	4	3				1	L Lobo J Sánchez	6	7
	WC	A Pavel G Trifu	6	2					A Kratzmann L Pimek	4	6
		A Kratzmann L Pimek	7	6											1	L Lobo J Sánchez	7	6
	4	P Albano À Corretja	4	3												C Brandi N Lapentti	5	2
		A Berasategui A Martín	6	6					A Berasategui A Martín	6	6	1
		C Brandi N Lapentti	6	6					C Brandi N Lapentti	7	4	6
		K Kinnear A Kitinov	4	4																		1	L Lobo J Sánchez	7	7
	WC	I Moldovan D Pescariu	5	4																			HJ Davids D Orsanic	5	5
		HJ Davids D Orsanic	7	6					HJ Davids D Orsanic	6	7
		B Coupe P Rosner	6	7					B Coupe P Rosner	3	5
	3	T Carbonell F Roig	4	5												HJ Davids D Orsanic	3	6	6
	Q	J Alonso E Sánchez	6	6	7										2	D Johnson F Montana	6	3	2
		B Haygarth G Van Emburgh	7	2	5			Q	J Alonso E Sánchez	6	4
	WC	G Cosac R Sabău	6	1	1			2	D Johnson F Montana	7	6
	2	D Johnson F Montana	4	6	6

References

External links

• Official results archive (ATP)
• Official results archive (ITF)